Slab, its types, design example and slab design excel sheet download.
slab
Slabs are
one of the most essential structural elements in construction, providing flat
surfaces such as floors and roofs.
They
distribute loads to beams and columns, ensuring the stability and functionality
of buildings.
Two common
types of slabs are one-way slabs and two-way slabs.
What is a One-Way Slab?
A one-way
slab is a reinforced concrete slab that primarily bends in one direction.
This happens
when the slab is supported on two opposite sides only, with the other two sides
free or simply spanning between beams.
The
length-to-breadth ratio (L/B) of a one-way slab is greater than or equal to 2.
Characteristics of One-Way Slabs:
- Bending occurs only in one
direction.
- Reinforcement is provided along
the shorter span (primary reinforcement) and shrinkage/temperature bars
are placed perpendicular to it.
- Commonly used in rectangular
rooms, corridors, and other spaces with significant length compared to
breadth.
What is a Two-Way Slab?
A two-way
slab bends in both directions and is supported on all four sides.
This type of
slab is used when the length-to-breadth ratio (L/B) is less than 2, enabling
the load to be distributed in two perpendicular directions.
Characteristics
of Two-Way Slabs:
- Bending occurs in both
directions.
- Reinforcement is provided in
both directions to handle bending moments.
- Suitable for square or nearly
square spaces, such as auditoriums, warehouses, and industrial buildings.
Differences Between One-Way and Two-Way Slabs:
Feature |
One-Way Slab |
Two-Way Slab |
Load Distribution |
Along one direction only |
Along both directions |
Support Conditions |
Two parallel sides |
All four sides |
L/B Ratio |
≥ 2 |
< 2 |
Reinforcement |
Along shorter span primarily |
In both directions |
Application Areas |
Corridors, narrow rooms |
Square or near-square rooms |
Design Example of a One-Way Slab
Problem: Design a one-way slab for a
residential building floor spanning 4 meters (width) and 10 meters (length).
The live load is 3 kN/m², and the floor finish load is 1 kN/m². Use M20 grade
concrete and Fe415 steel.
Step 1:
Determine Effective Span
The
effective span for the one-way slab is the shorter span, i.e., 4 meters.
Step 2:
Calculate Total Load
Dead Load =
Self-weight of the slab = 25 × Thickness (assume 150 mm thickness initially)
Dead Load =
25 × 0.15 = 3.75 kN/m² Total Load = Dead Load + Live Load + Floor Finish Load =
3.75 + 3 + 1 = 7.75 kN/m²
Step 3:
Moment Calculation
Factored
Load = 1.5 × 7.75 = 11.625 kN/m² Factored Bending Moment (M) = wL²/8 = (11.625
× 4²) / 8 = 23.25 kN.m
Step 4:
Reinforcement Design
Using M20
concrete and Fe415 steel, calculate the area of steel (Ast) using the bending
moment formula:
Ast = (M ×
10⁶) / (0.87 × fy × d)
Assume an
effective depth (d) of 125 mm. Ast = (23.25 × 10⁶) / (0.87 × 415 × 125) =
419.77 mm² Use 12 mm diameter bars spaced at 150 mm center-to-center.
Design
Example of a Two-Way Slab
Problem: Design a two-way slab for a hall
measuring 6 m × 6 m with a live load of 4 kN/m² and floor finish of 1.5 kN/m².
Use M25 grade concrete and Fe500 steel.
Step 1:
Check Slab Type
L/B = 6/6 =
1 (less than 2). Therefore, it is a two-way slab.
Step 2:
Calculate Total Load
Dead Load =
25 × Thickness (assume 150 mm initially) Dead Load = 25 × 0.15 = 3.75 kN/m²
Total Load = Dead Load + Live Load + Floor Finish Load = 3.75 + 4 + 1.5 = 9.25
kN/m²
Step 3:
Moment Calculation
Factored
Load = 1.5 × 9.25 = 13.875 kN/m² Moments are calculated using coefficients from
IS 456:2000: Mx = αx × w × L², My = αy × w × L² Assume αx = 0.052 and αy =
0.045 for simply supported edges.
Mx = 0.052 ×
13.875 × 6² = 25.93 kN.m My = 0.045 × 13.875 × 6² = 22.41 kN.m
Step 4:
Reinforcement Design
For Mx and
My, calculate the reinforcement using: Ast = (M × 10⁶) / (0.87 × fy × d) Assume
an effective depth (d) of 125 mm for initial design. Astx = (25.93 × 10⁶) /
(0.87 × 500 × 125) = 477.25 mm² Asty = (22.41 × 10⁶) / (0.87 × 500 × 125) =
412.07 mm²
Use 10 mm
bars at 150 mm c/c for Astx and 12 mm bars at 200 mm c/c for Asty.
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